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5a+8a=13a^2
We move all terms to the left:
5a+8a-(13a^2)=0
determiningTheFunctionDomain -13a^2+5a+8a=0
We add all the numbers together, and all the variables
-13a^2+13a=0
a = -13; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-13)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-13}=\frac{-26}{-26} =1 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-13}=\frac{0}{-26} =0 $
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